In the following pic-
shouldn't it be $\Bbb{Z}_{{p_j}-1}$ instead of $\Bbb{Z}_{p_j}$.
I think so because Aut$(Z_{p^n}) \cong Z_{p-1} \oplus \underbrace {(Z_p\oplus Z_p \oplus \dots Z_p)}_{n-1\ \text{times}} $.
Am I correct?
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It doesn't look right at all. The automorphism group of a cyclic group of order $p^n$ with $p$ odd is cyclic of order $(p-1)p^{n-1}$ (which is isomorphic to $C_{p-1} \times C_{p^{n-1}}$) and for $p=2$ and $n \ge 2$, it is isomorphic to $C_2 \times C_2^{n-2}$. – Derek Holt Jul 05 '15 at 20:24
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yes. Thanks.... – blabla Jul 05 '15 at 20:29