1

For all uncountable set,

Is there an uncountable subset such that its complement is also uncountable?

How can I prove this?

Asaf Karagila
  • 405,794
Evzone
  • 151

1 Answers1

1

Assuming AC the answer is yes. (I'm not sure what the answer is in ZF).

Hint: Think about even and odd ordinals, and how you might use their existence for your purposes. This actually proves a bit more namely that you can split any infinite set into two sets with cardinality equal to the original set.

DRF
  • 5,282