For all uncountable set,
Is there an uncountable subset such that its complement is also uncountable?
How can I prove this?
For all uncountable set,
Is there an uncountable subset such that its complement is also uncountable?
How can I prove this?
Assuming AC the answer is yes. (I'm not sure what the answer is in ZF).
Hint: Think about even and odd ordinals, and how you might use their existence for your purposes. This actually proves a bit more namely that you can split any infinite set into two sets with cardinality equal to the original set.