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To use the Alternating Series Test on a series: $$ \sum_{n=k}^{\infty} (-1)^nb_n, \quad b_n\geq 0 $$ I have been told that I need to check that

  1. $b_{n+1} \leq b_n$ for all $n$
  2. $\lim_{n\to \infty} b_n= 0$.

But I can't understand why it isn't enough to check the limit part. IF the limit goes to zero, don't the $b_n$'s have to be decreasing?

John Doe
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3 Answers3

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Consider the sequence $$1,0,\frac{1}{2},0,\frac{1}{3}, ...$$, or if you want a more clearly alternating sequence then consider $$1, -1, \frac{1}{2}, -\frac{1}{4}, \frac{1}{3}, -\frac{1}{16}, ..., \frac{1}{n}, -\frac{1}{4^n},...$$

Both of these sequences satisfy the limit $\to 0$ (and the second explicitly alternates). But the series associated to either example diverges. The reason here is that the positive terms are much bigger than the negative terms. This is very visible in the second example, but distilled in the first.

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No. For example, if $b_n$ is $1/n$ for even $n$ and $0$ for odd $n$, then $\lim\limits_{n\to \infty} b_n = 0$ but $b_n$ is not decreasing.

kobe
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As another example, you could consider the series

$\displaystyle \frac{2}{1}-\frac{1}{1}+\frac{2}{2}-\frac{1}{2}+\frac{2}{3}-\frac{1}{3}+\cdots+\frac{2}{n}-\frac{1}{n}+\cdots$.

This is an alternating series whose terms approach 0, but the terms are not decreasing in absolute value

(since $\displaystyle\frac{1}{n}<\frac{2}{n+1}$ for $n>1$).

user84413
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