The Exercise is
Computer A has a main memory of size HA 2 MiB, and computer B has a main memory of HB = 256 MiB. Both computers process single transactions that have a size of s=84 KiB. Each of the computers loads a maximum number of transactions into the main memory so that at least 512 KiB are still reserved for the processing algorithm. After that, all transactions in the main memory are processed as a batch. The time to load a transaction is 2 ms in both systems. Computer A processes a transaction in 4 ms, computer B needs 7 ms to process a transaction.
Which of the two systems is faster with the processing of all transactions finished? Is there a number of transactions that are processed equally fast by both systems? Justify your answers and give the complete calculation path to your answer.
I need to know if my answer is correct, and if not, why.
My answer would be:
Computer A has 2048 KiB - 512 KiB = 1536 KiB
1536 KiB / 84 KiB = 18 transactions
18 transactions * 4 ms = 72 ms
Computer B has 262144 KiB - 512 KiB = 261632 KiB
261632 KiB / 84 KiB = 3114 transactions
3114 transactions * 7 ms = 21798 ms
Computer B takes longer to process than computer A.
Now one question I have is that I'm pretty sure that this is not the right answer to this exercise, because the 2 ms, for loading the transaction, are not included in my answer.
What did I do wrong?
