The curve equation for P-256 is:
NIST P-256
y^2 = x^3-3x+41058363725152142129326129780047268409114441015993725554835256314039467401291
Below I am generating key data, including the secret key "d".
Can someone please help me:
1-Convert and plug in the 2 points below into the above equation to ensure the points lie on the curve.
2-Show me, using the curve equation above, how I can determine that x+y will land back on the curve as d, all values shown below?
Use jwcrypto to generate key data
key_data = jwk_crypto.JWK.generate(kty='EC', crv='P-256')
private_key_data = key_data.export(as_dict=True)
print(json.dumps(private_key_data, indent=2))
===>
{
'kty': 'EC',
'crv': 'P-256',
'x': 'vddm_d3R2dYNICxh2D93hjBZyEbpIWSW0fhPUXhHCgc',
'y': 'BjcTCjAp6oqDRbWDSCiCMxSKMDEAe4rAwYJqXHEbO98',
'd': 'B_nLv2KHBVUZEx6KSNULf3ZqZlYaVrpp8J7ncORbS_U'
}
