CharSequence to int

Question

Is there a Way to converte a Charsequence or a String to an Ingeter?

CharSequence cs = "123";
int number = (int) cs;

I'm a Noob. Solution:

CharSequence cs = "123";
int number = Integer.parseInt(cs);

Answer 1

Use Integer.parseInt(). If your CharSequence is not a String, then you need to convert it first using toString().

int number = Integer.parseInt(cs.toString());

Answer 2

Since Java 9 you can use Integer.parseInt(CharSequence s, int from, int to, int radix) to parse integers from any CharSequence without first converting it to a String:

CharSequence cs = new StringBuilder("4711");
int value = Integer.parseInt(cs, 0, cs.length(), 10);

Answer 3

use this

int i=Integer.parseInt(cs.toString())

Answer 4

Integer.parseInt(cs.toString())

Answer 5

Use the parsers from the Wrapper classes (Integer, Float, etc)...

public static void main(String[] args) {
    String s = "1";
    int i = Integer.parseInt(s);
    System.out.println(i);
}

Answer 6

Using Kotlin

CharSeqString.toString.toInt()

Answer 7

From Editview component,

TextView txtYear = (TextView) findViewById(R.id.txtYear);
int intYear = Integer.parseInt(txtYear.getText().toString());