How to send Model to _Layout.cshtml (I need to send another model to Index view too)

Question

I need to send 2 different Models, one to Index view and another one to _Layout.cshtml, how I can do it?

My HomeController:

[Route("")]
public ActionResult Index()
{
    HomeViewModel model = new HomeViewModel();
    model.A = _repoA.GetLatest(4);
    model.B = _repoB.GetLatest(4);
    model.C = _repoC.GetLatest(4);
    return View(model);
}

I don't like using ViewBag, ViewData & ..., I'm looking for passing the model in same way as we passing model to Views.

possible duplicate of [ASP.NET MVC Razor pass model to layout](http://stackoverflow.com/questions/4154407/asp-net-mvc-razor-pass-model-to-layout) — Lordbalmon, Aug 08 '15 at 19:52
Why not create a partial view with the model and render it in the layout. — pool pro, Aug 08 '15 at 20:59
That's sounds great, but I prefer do it without this solution, is there any way to sending model direct to _layout? — Mehdi Dehghani, Aug 08 '15 at 21:15
Use a partial view or child action. Many examples -- See [here](http://stackoverflow.com/questions/11459390/asp-net-mvc-3-partial-view-in-layout-page), [here](http://stackoverflow.com/questions/10552502/passing-data-to-a-layout-page), [here](http://stackoverflow.com/questions/5938837/asp-net-mvc-how-to-have-a-controller-in-shared-view)... — Jasen, Aug 08 '15 at 21:25
Please read the question again, I wanna send to both of `index view` & `partial view` !!! — Mehdi Dehghani, Aug 09 '15 at 04:30

score 3 · Answer 1 · answered Mar 09 '16 at 21:47

3

You can place this in your Layout to load a partial each time... Pretty useful for loading in a piece of a dynamic menu or a widget on each page.

Along with this line in your layout you can just do your Index page as you normally would.

@{ Html.RenderAction("_widget", "Home"); }

answered Mar 09 '16 at 21:47

Mike Wallace

543
4
15

We can't use RenderAction in _Layout.cshtml. It leads to recursive call – MirrorBoy May 05 '17 at 09:44

score 1 · Answer 2 · edited May 23 '17 at 12:24

You'll need to send it along in the ViewBag. I found the best bet was to make an abstract controller:

public abstract class ApplicationController : Controller
{
    protected ApplicationController()
    {
         UserStateViewModel = new UserStateViewModel();
         //Modify the UserStateViewModel here.
         ViewBag["UserStateViewModel"] = UserStateViewModel;
    }

    public UserStateViewModel UserStateViewModel { get; set; }
}

Then, have all of your controllers inherit from this abstract controller.

In your _Layout.cshtml (or whatever you called it), you'll need to include the following at the top:

@{
     var userState = (UserStateViewModel)ViewBag.UserStateViewModel;
}

Duplicate but refined from the 2nd answer to ASP.NET MVC Razor pass model to layout.

Is there a better way to do this? it seems that it couples your controller to the View. The whole point of the MVC pattern is to be able to decouple. — leat, Feb 21 '23 at 07:27

How to send Model to _Layout.cshtml (I need to send another model to Index view too)

2 Answers2