while(false){
x = 3;
}
if(false){
x = 5;
The compiler will complain and not compile the while statement, unreachable code. But it still compile for the if statement to have unreachable code. Reason?
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It's not fine for the `if`. You get a warning about *dead code*. – Luiggi Mendoza Jan 30 '15 at 19:35
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@LuiggiMendoza true.but the code still compile. I wonder why it is designed this way? – OPK Jan 30 '15 at 19:36