Questions tagged [quintics]

Questions about polynomials with degree $5$. There is no general algebraic solution to these equations as proven by the Abel-Ruffini theorem, although some quintics are solvable.

A quintic equation is an equation in the form:

$$ax^5 + bx^4 + cx^3 + dx^2+ex+f = 0 $$

where $a,b,c,d,e,f$ are members of a field, typically either the rational numbers, the real numbers, or the complex numbers, and $a \ne 0$.

According to the Fundamental Theorem of Algebra, quintic equations always have $5$ roots. This number includes complex roots, as well as repeated roots.

The Abel-Ruffini theorem states that there is no algebraic solution to a quintic equation with arbitrary coefficients. An algebraic solution is a solution which uses only addition, subtraction, multiplication, division, exponentiation, and $n$th root extraction. However, this theorem does not imply that all quintics do not have an algebraic solution (one counterexample is $(x-1)^5 = 0$), or that a specific quintic equation is not solvable using radicals. Sextic ($6$th degree) equations and polynomials of higher degrees also do not have a general algebraic solution under this theorem.

There are several methods to find the roots of solvable quintics. One method is to use the Tschrinhaus transformation $x = y - \frac{b}{5a}$, which depresses the quintic or removes the fourth-degree term. Then the original quintic has a solvable root if the transformed quintic is a product of lower-order polynomials with rational coefficients, or if Cayley's resolvent, the polynomial $P^2 - 1024z \Delta$ is solvable. Alternatively, quintics of the form $x^5+ax+b = 0$ can be represented parametrically using the Bring-Jerrard form.

The roots of quintics and other higher-order polynomials can be approximated by Newton's method, the secant method, the method of false position, Padé approximants, and other root-finding algorithms.

Quintic equations are relevant to problems in celestial mechanics. Solving for the locations of the Lagrangian points of an astronomical orbit, where the masses of both objects are non-negligible, requires solving a quintic. For example, finding a stable location for a satellite between the Sun and the Earth requires solving a quintic.

References (not for academic use):

https://en.wikipedia.org/wiki/Quintic_function

https://en.wikipedia.org/wiki/Abel%E2%80%93Ruffini_theorem

https://mathworld.wolfram.com/QuinticEquation.html

Further reading:

https://archive.lib.msu.edu/crcmath/math/math/q/q111.htm

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How to solve fifth-degree equations by elliptic functions?

From F. Klein's books, It seems that one can find the roots of a quintic equation $$z^5+az^4+bz^3+cz^2+dz+e=0$$ (where $a,b,c,d,e\in\Bbb C$) by elliptic functions. How to get that? Update: How to transform a general higher degree five or higher…
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The most generic radicals-solvable quintic

It's well known that it is impossible to solve a generic quintic equation in terms of radicals involving its coefficients. However: what's the "most generic" quintic equation that is still possible to solve using radicals? If we think of a quintic…
Alma Do
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How large is the gap in Ruffini's 1813 proof that there is no general quintic formula?

I'm reading Ruffini's final attempt at showing there is no general quintic formula which appeared in 1813 see here. (This is a much shorter proof than his first proof of 1799 in his Teoria generale delle equazioni... which proceeds via a lengthy…
CJO
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On solvable quintics and septics

Here is a nice sufficient (but not necessary) condition on whether a quintic is solvable in radicals or not. Given, $x^5+10cx^3+10dx^2+5ex+f = 0\tag{1}$ If there is an ordering of its roots such that, $x_1 x_2 + x_2 x_3 + x_3 x_4 + x_4 x_5 + x_5…
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Solving quintic equations of the form $x^5-x+A=0$

I was on Wolfram Alpha exploring quintic equations that were unsolvable using radicals. Specifically, I was looking at quintics of the form $x^5-x+A=0$ for nonzero integers $A$. I noticed that the roots were always expressible as sums of…
Moko19
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Factor $x^5-x+15$

It's possible to factor $x^5-x+15$. WolframAlpha gives the answer of: $$(x^2+x+3)(x^3-x^2-2x+5)$$ According to the wikipedia article on quintic functions, the general form $x^5-x+a$ is factorable only when $a=±15$, $±22440$, or $±2759640$. Question:…
KKZiomek
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Expressing the roots of $x^4+ax^3+2x^2-ax+1 = 0$ in terms of trigonometric functions

I know one root of the equation $$x^4+ax^3+2x^2-ax+1 = 0 \tag1$$ is, $$x_1 = \tan\left(\frac{1}{4}\arcsin\frac{4}{a}\right)$$ How to find the other three roots of eq.1 expressed similarly in terms of trigonometric and/or inverse trigonometric…
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How to solve a quintic polynomial equation?

I know that not all quintics are solvable. But how do I identify the class of solvable ones?
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Quintic reciprocity conjecture

Let $p=x^4 + 25x^2 + 125$ be a prime. Prove that $2$ is a quintic residue $\pmod p$, and therefore $y^5=2\pmod p$ is solvable. A similar example was first conjectured by Euler: If $p=x^2 + 27$ is a prime, then $2$ is a cubic residue $\pmod p$,…
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Explicit example of a quintic threefold with 2875 distinct lines

A generic quintic threefold has 2875 lines. Is there an example of a quintic threefold explicitly defined by a polynomial that can be proven to have exactly 2875 distinct lines? I am particularly interested in an answer in the following form.…
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On generalizing Ramanujan cosine sums to $\sqrt[5]{x_1}+\sqrt[5]{x_2}+\sqrt[5]{x_3}+\sqrt[5]{x_4}+\sqrt[5]{x_5} = \sqrt[5]{z}$?

I. Cubic In 2013, I asked a question regarding an identity by Ramanujan of form, $$\sqrt[3]{0+2\cos\tfrac{2\pi}{7}}+\sqrt[3]{0+2\cos\tfrac{4\pi}{7}}+\sqrt[3]{0+2\cos\tfrac{6\pi}{7}} = \sqrt[3]{+5-3\,\sqrt[3]{7}}$$ which later turned out to have a…
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The solution to the principal quintic via the Brioschi and Rogers-Ramanujan cfrac $R(q)$

In this interesting post, it quotes a paper that to write down the complete solution (not in radicals) of the general quintic, one would need "a piece of paper as big as a large asteroid". Probably an exaggeration, but perhaps we can reduce the…
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How do I solve the quintic $n^5-m^4n+\frac{P}{2m}=0$ for $n$?

I want to solve the following equation for $n$ in terms of $P$ and $m$. $$n^5-m^4n+\frac{P}{2m}=0$$ I've bought and read many books, including "Beyond The Quartic Equation" but I've either missed something or do not have enough background or…
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Is there a way to reduce a specific quintic to cubic?

A polynomial in two variables, $t$ and $c$, is quintic in $t$ and quartic in $c$: \begin{align} 16\,t^5 -8\,c (5\,c +2) t^4 +c^2 (25\,c^2+20\,c + 36) t^3& \\ -4\,c (11\,c^3+8\,c^2+5\,c+2) t^2& +8\,c^2 ( 3\,c^2+3\,c+2 ) t -4\,c^3…
g.kov
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Why does $x^2+47y^2 = z^5$ involve solvable quintics?

(See 2025 update below.) This is related to the post on $x^2+ny^2=z^k$. In response to my answer on, $$x^2+47y^2 = z^k\tag1$$ for $k=3$ and where z is not of form $p^2+nq^2$, Will Jagy provided one for $k=5$, $$ (14p^5 + 405p^4q + 3780p^3q^2 +…
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