Questions tagged [permanent]

A function on square matrices which can be given as a polynomial of the matrix entries. A special case of the "immanant" of a matrix. Used primarily in combinatorics, graph theory, and quantum field theory.

The permanent $\DeclareMathOperator\perm{perm} \perm$ is a function defined for square matrices. Given an $n\times n$ matrix $A = (a_{ij})_{i,j\in \{1,\dots,n\}}$, we define its permanent as $$ \perm(A) = \sum_{\sigma \in S_n} \prod_{i = 1}^n a_{i\sigma(i)} $$ where $S_n$ is the permutation group on $n$ objects.

Observe that the formula is very similar to the formula for the determinant of a matrix, which is given by $$ \det(A) = \sum_{\sigma \in S_n} \operatorname{sgn}(\sigma) \prod_{i = 1}^n a_{i\sigma(i)} $$ with only the omission of the "sign" of the permutation $\sigma$ from the formula.

As an example, consider the $2\times 2$ matrix $$ A = \begin{pmatrix} a & b \\ c & d \end{pmatrix} $$ We can compute $$ \det(A) = ad - bc$$ while $$ \perm(A) = ad + bc$$

Many of the algebraic properties of the determinant has similar analogues for the permanent:

  • The determinant is invariant under signed permutations of rows and columns. The permanent is invariant under all permutations of rows and columns.
  • The determinant of the transpose $A^T$ is equal to the determinant of $A$. We also have $\perm(A^T) = \perm(A)$.
  • For an $n\times n$ matrix $A$, we have $\det(\lambda A) = \lambda^n \det(A)$. Similarly $\perm(\lambda A) = \lambda^n \perm(A)$ (so that the functions $\det$ and $\lambda$ are both homogeneity $n$).

But the geometric properties of determinant that makes it so useful in linear algebra do not typically have analogues for the permanent.

  • Given two square matrices $A,B$ of the same size, we have $\det(A B) = \det(A) \det(B)$. In general the statement "$\perm(AB) = \perm(A) \perm(B)$" is false.
  • A matrix is invertible if and only if it has non-vanishing determinant. There are non-invertible matrices with non-vanishing permanent, as well as invertible matrices with vanishing permanent.
58 questions
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What is the number of $n \times n$ binary matrices $A$ such that $\det(A) = \text{perm}(A)$?

Recall that the permanent is the 'positive analog' of the determinant whereby the signs in the cofactor expansion process are taken as positive. That is, the permanent is the immanant corresponding to the trivial character. Many enumerative problems…
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Why is the permanent of interest for complexity theorists?

Studying a bit about the determinant and the permanent, I'm told that although both concepts have very similar formulas, the permanent was of not much interest historically - it was until later that complexity theorists became more curious about…
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If a stochastic matrix has unit permanent, is it a permutation matrix?

In this question, a stochastic square matrix is a real square matrix where all the rows sum up to $1$ and all the entries are between $0$ and $1$. Permutation matrices are examples of stochastic square matrices, for which the permanent $$…
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Geometric interpretation of the permanent

The permanent of a square matrix $M = \left( m_{i,j} \right)$ is defined as follows: $$ \operatorname{perm} (M) = \sum_{\sigma\in S_n}\prod_{i=1}^{n} m_{i,\sigma(i)} $$ The permanent is quite similar to the determinant of a square matrix, which is…
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What makes the permanent a lot more difficult than the determinant?

The permanent of an $n$-by-$n$ matrix $A = \left( a_{i,j} \right)$ is defined as follows $$ \operatorname{perm}(A) = \sum\limits_{\sigma \in S_n} \prod\limits_{i=1}^n a_{i,\sigma(i)} \tag{1} $$ On the other hand, the determinant of $A$ is defined as…
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Permanent of a low-rank matrix is easy to calculate?

In this paper, Aaronson and Arkhipov use the following lemma (lemma 67 in the paper): Let $V \in \mathbb{C}^{n \times n}$ be a matrix of rank $k$. Then $\operatorname{Per}(V + I)$ is computable exactly in $n^{O(k)}$ time. Unfortunately, they refer…
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Special formula for the permanent of the sum of two matrices

Dear math stack exchange community, I was told that in the paper http://www.tandfonline.com/doi/abs/10.1080/03081088708817770 there was a formula for the permanent of the sum of two matrices $X$ and $Y$ via permanents of certain submatrices of $X$…
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What is an intuition behind permanent?

I would like to know what is your intuition behind permanent of a matrix. For me, it looks like someone came and saw determinant, deleted permutation sign and voila, we have permanent and it counts the number of perfect matchings. But I am sure that…
user320254
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Efficient estimation of Perron–Frobenius eigenvalues for $\ell$-RLL constrained composite DNA without full matrix construction

I am studying constrained coding for composite DNA (based on arXiv:2501.10645), where each composite symbol represents a mixture of nucleotides. To enforce a maximum runlength $\ell$, they model valid sequences using a transition matrix over states…
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If $A \succ B$, then $\operatorname{per} A \ge \operatorname{per} B$

Let the matrices $A, B, A-B$ be positive definite. How to show $\operatorname{per} A \ge \operatorname{per} B$, where $\operatorname{per}$ denotes the permanent function? Also, if $A$ is a $n\times n$ doubly stochastic matrix that is also positive…
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What is the use of a Permanent and how is it different and / or similar to Determinant?

I am a graduate student in Mathematics. I am interested in Differential Geometry and Topology. Recently I came across a new terminology namely the permanent of a square matrix. I saw it as being defined in almost the same way as the determinant,…
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Closed-form expression for the permanent of $1_n 1_n^\top - 2 I_n$

Find a formula for the permanent of the following square matrix with $-1$ on the main diagonal and $1$ everywhere else. $$ A = \begin{bmatrix} -1 & 1 & 1 & \dots & 1 \\ 1 & -1 & 1 & \dots & 1 \\ 1 & 1 & -1 & \dots & 1…
Noam
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"Absolute" version of determinant

It is well known that for a matrix $A = (A_{i,j})$, the determinant of $A$ is $$\det(A) = \sum_{\sigma \in S_n} \mbox{sgn} (\sigma)\prod_{i \in [n]} A_{i,\sigma(i)}.$$ Is there any way to manipulate the matrix to obtain, or any existing…
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Permanent generating function identity for $\exp{\mathbf{x^{T}}A\mathbf{y}}$

In this paper, there's an identity that I can't prove to my satisfaction, (there's a similar statement in here) which is that, given a permanent of a $(\mathbf{k,l})$-replicated matrix $A$, (written $A^{(\mathbf{k,l})}$), $$\sum_{\mathbf{k,l}\geq…
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How to invert this function on matrices that involves the permanent?

I'm interested in understanding whether a particular natural function on matrices, closely related to the permanent of a matrix, is invertible, and whether its inverse admits a simple closed form. The function $f$ I'm concerned with maps doubly…
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