Questions tagged [group-schemes]

Use this tag for scheme-theoretic and category-theoretic questions about group schemes, as well as those group schemes that are not algebraic groups. A group scheme G over a scheme S is simply a group object in the category of schemes over S. Finite type group schemes over a field are represented by varieties, and considered algebraic groups; for questions specific to algebraic groups use the [algebraic-groups] tag

A group scheme $G$ over a scheme $S$ is simply a group object in the category of schemes over $S$.

In other words, a group scheme consists of a scheme $G$ over $S$ and $3$ distinguished morphisms of $S$-schemes:

  • Multiplication $m \colon G \times G \to G$
  • Inverse $i \colon G \to G$
  • Identity $e \colon S \to G$

such that for all schemes $T$ over $S$, the morphisms $m$, $i$, and $e$ satisfy the axioms of a group structure on $G(T) = \mathrm{Hom}_S(T, G)$.

By transitivity of the group's action on itself, it must be either smooth or non-reduced everywhere. Thus all reduced group schemes $G$ of finite type over a field $k$ are smooth varieties, making them algebraic groups. Algebraic groups include linear algebraic groups, such as reductive groups and parabolic groups, as well as abelian varieties. Non-algebraic group schemes include non-smooth groups, such as the kernel of the Frobenius $F: \mathbb{G}_a(\mathbb{F}_p) \to \mathbb{G}_a(\mathbb{F}_p)$, as well as infinite-dimensional group schemes such as the positive loop group $L^+G$ of an affine group scheme. The category of affine group schemes is the opposite category of Hopf algebras.

236 questions
16
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Are the roots of unity the only algebraic subgroups of the multiplicative group?

$\newcommand{\G}{\mathbb{G}}$ Let $k$ a field (or maybe more generally an arbitrary ring with connected spectrum), $\G_m$ the multiplicative group over $k$. Are the $\mu_n = \{x^n = 1\}$ the only $k$-subgroup schemes of $\G_m$? What is the best way…
14
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What does $\mathbf G_m$ really mean?

My understanding is that $\mathbf G_m$ stands for $k^*$ (the multiplicative group of the field $k$) as a group scheme. But I have also seen symbols like $H^1(X_{\text{et}},\mathbf G_m)$. Is this talking about the first cohomology group of $X_{et}$…
grok
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13
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Motivation?: Lie algebra and algebraic group Cohomology

This is just an apriori question to get a motivational heuristic idea: If an algebraic group G (more generally, G an affine group scheme), is connected over an algebraically closed base-field k. Then are there relationships between its rational…
10
votes
1 answer

$k$-group endomorphisms of the multiplicative group scheme for $k$ a connected ring.

I wanted to verify that for a connected ring $k$ (i.e. a ring with connected spectrum, or equivalently without idempotents other than $0$ and $1$) the group of $k$-endomorphisms of the multiplicative group $\mathbf{G}_m$ over $k$ can be identified…
10
votes
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surjective morphism of algebraic groups and fppf topology

I'm reading Milne's course notes on Affine Group Schemes: http://www.jmilne.org/math/CourseNotes/AGS.pdf In Definition 7.1 it says: " A homomorphism $G \to Q$ of affine groups is said to be surjective (and $Q$ is called a quotient of $G$) if the…
9
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2 answers

Is $\mathrm{Gal}(\overline{\mathbb Q}/\mathbb Q)\cong\mathrm{Spec}(\overline{\mathbb Q}\otimes\overline{\mathbb Q})$ a group scheme

This question gives a homeomorphism $\mathrm{Gal}(\overline{\mathbb Q}/\mathbb Q)\cong\mathrm{Spec}(\overline{\mathbb Q}\otimes_\mathbb Q\overline{\mathbb Q})$, sending $\sigma\in\mathrm{Gal}(\overline{\mathbb Q}/\mathbb Q)$ to $\mathfrak…
9
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Specializing group scheme embedding

Let $R$ be a DVR with algebraically closed residue field $k$ and fraction field $K$. Let $f:G\longrightarrow H$ be a morphism of commutative $R$-group schemes. Suppose that $G$ is an abelian scheme over $R$ and that $f_K$ is an embedding. Then, is…
pozio
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9
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1 answer

How can an elliptic curve be regarded as a group scheme?

If I understand correctly: A scheme is a functor $\mathbf{CRing} \rightarrow \mathbf{Set}$ satisfying certain axioms. A morphism of schemes is a natural transformation. A group scheme is a group object in the category of schemes, so in particular…
9
votes
2 answers

What is difference between constant group scheme associated with cyclic group and $\mu_n$

Let $k$ a field. Let $\operatorname{char}(k) \not\mid n$. Consider the two group schemes $\mu_n=spec(k[t]/(t^n-1))$ and $\underline{\mathbb{Z}/n\mathbb{Z}}$ the constant group scheme associated to the cyclic group ${\mathbb{Z}/n\mathbb{Z}}$. Are…
9
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2 answers

Why are finite group schemes usually assumed flat?

I am learning about group schemes at the moment. When it comes to finite group schemes, every author I have read so far restricts himself to the case of schemes which are also flat over the base, sometimes with the remark that it does not make much…
sf1
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8
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Deligne category $\underline{\mathrm{Rep}}(GL_t)$ is abelian

I am reading Deligne & Milne's notes on tannakian categories. In this document, the authors defin the notion of Deligne categories, $\underline{\mathrm{Rep}}(GL_t)$, let me give a rough introduction to this sort of categories and what I am confused…
8
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When $\phi_{\mathcal L}=0$ for $\mathcal L$ a line bundle over an abelian scheme $X/S$

Let $X\rightarrow S$ be a projective abelian scheme. To a line bundle $\mathcal L$ on $X$, we associate its Mumford line bundle $\Lambda(\mathcal L):= \mu^{\star}\mathcal L\otimes p_1^{\star}\mathcal L^{-1}\otimes p_2^{\star}\mathcal L^{-1}$ on…
8
votes
1 answer

Abelian group structure on roots of a polynomial

Assume $f \in \Bbb Z[x]$ is a monic polynomial, s.t for every commutative ring $R$, the solutions of $f(x)=0$ in $R$ can be endowed with an abelian group structure that is functorial respect to $R$. Some examples of f include $ f(x)=x^n-1, …
user395911
7
votes
2 answers

Algebraic torus and generic points

Many definitions of the multiplicative group scheme $G_m$ define it as $\operatorname{Spec}\mathbb{C}[x, x^{-1}]$. But the Spec of that ring is actually $\mathbb{C}^*\cup\{\eta\}$, with an extra generic point. So when you want to define…
A.D.
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7
votes
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How does Hartshorne's definition of group schemes encode the law for the neutral element?

Hartshorne's Algebraic Geometry says A scheme $X$ with a morphism to another scheme $S$ is a group scheme over $S$ if there is a section $e\colon\;S\to X$ (the identity) and a morphism $\rho\colon\;X\to X$ over $S$ (the inverse) and a morphism…
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