Could we find the OGF for the sequence $k^3, k \geq 2$?
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Did you try anything? – Pedro May 05 '14 at 03:21
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Yes, tried to differentiate some elementary generating functions... – cinvro May 05 '14 at 03:27
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Apply the operator $(xD)^3= (xD)(xD)(xD) $ to $\frac{1}{1-x}$ gives your the answer.
Note:
$$D =\frac{d}{dx}. $$
Mhenni Benghorbal
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