1

Could we find the OGF for the sequence $k^3, k \geq 2$?

cinvro
  • 349

2 Answers2

2

A related problem

Apply the operator $(xD)^3= (xD)(xD)(xD) $ to $\frac{1}{1-x}$ gives your the answer.

Note:

$$D =\frac{d}{dx}. $$

1

Hint: $~k^3x^k=(x\frac{\partial}{\partial x})^3x^k$

anon
  • 155,259