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So I was faced by this problem: If $p,q \in K[x]$, with $q = q_{0}^{\alpha_{0}} \dots q_{m}^{\alpha_{m}}$, all of $q_{i}$ irreducible and $\alpha_{i}$ natural numbers. So, there is some $p_{0} \dots p_{m} \in K[x]$ where $$ \frac{p}{q}=\sum_{j = 0}^{m}\frac{p_{j}}{q_{j}^{\alpha_{j}}}. $$


So, at first sight, it looks a lot like the partial fractions decomposition, which we use a lot in Calculus, but I can't prove this. Any help, I will be appreciated. Thanks in advance!

Bill Dubuque
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After some research, I've found a text that explain this. You may click here. And look for propositions $3.5$ and $3.6$.