If X and Y are independent exponential random variables with respective parameters λ1 and λ2, how do I find the distribution of Z = X/Y ?
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I actually ran into this problem not so long ago. Replace the variables $X_1$ with X and $X_2$ with Y and you should receive the same answer.

Shrey
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Hint: First find the domain of $Z$. Then for any $z\in D_Z$ we have \begin{equation} P(Z\le z) = P(X/Y\le z) = P(X\le zY) = \int_{y\in D_y}P(X\le zy)f_Y(y)dy. \end{equation} Solve this and differentiate with respect to $z$ to find the density function of $Z$.
Marc
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