0

According to the answer in What are the consequences of Diffie Hellman problem in P?, it appears we believe Discrete Logarithm and Diffie-Hellman are equivalent problems.

We also know if Discrete logarithm is easy, the factoring is easy.

Can we conclude and say breaking Diffie-Hellman yields a polynomial time algorithm for integer factoring? What would such an algorithm look like?

Turbo
  • 1,045
  • 6
  • 15

0 Answers0